已知岩样的重度 gamma = 22.5 , (kN) / (m)^3，相对密度 G_s = 2.8，天然含水率 omega = 8%，试计算该岩样的孔隙率 mu，干重度 gamma_d 及饱和重度 gamma_(sat)。（本题 10 分）

根据题意，设 $V = 1 \, \text{m}^3$，则： \[ W_s = \frac{\gamma}{1 + \omega} = \frac{22.5}{1.08} = 20.833 \, \text{kN}, \quad W_w = 0.08 W_s = 1.667 \, \text{kN} \] \[ \gamma_d = \frac{W_s}{V} = 20.833 \, \text{kN/m}^3 \] \[ V_s = \frac{W_s}{G_s \rho_w} = \frac{20.833}{28} = 0.744 \, \text{m}^3, \quad V_v = 1 - 0.744 = 0.256 \, \text{m}^3 \] \[ n = 25.6\% \] \[ \gamma_{\text{sat}} = \frac{W_s + \rho_w V_v}{V} = \frac{20.833 + 2.56}{1} = 23.393 \, \text{kN/m}^3 \] 最终结果： \[ n = 25.6\%, \quad \gamma_d = 20.83 \, \text{kN/m}^3, \quad \gamma_{\text{sat}} = 23.39 \, \text{kN/m}^3 \]