[题1.12]用图形法将下列函数化简成为最简与或式:-|||-(1) _(1)=ABCD+ABCD+ABCD+ABCD+ABCD+ABCD-|||-(2) _(2)=overline (A)overline (CD)+overline (A)Boverline (D)+ABD+Aoverline (CD)-|||-(3) _(3)=AB+Boverline (C)overline (D)+ABD+overline (A)Boverline (C)D-|||-(4) _(4)=overline (A)overline (B)C+AD+overline (BD)+overline (CD)+overline (AC)+overline (A)D-|||-(5) _(5)=ABoverline (CD)+overline (A)B+overline (A)overline (B)overline (D)+Boverline (C)+BCD-|||-(6) _(6)=overline (A)overline (B)D+overline (A)Boverline (C)+BCD+ABoverline (C)D+overline (A)overline (B)overline (C)overline (D)-|||-CD-|||-AB 00 01 11 10 CD-|||-AB 00 01 ll 10-|||-00 1 1 1-|||-0 1-|||-01-|||-01 1 1 1-|||-11-|||-11 1 ① 1)-|||-10 1 1 1 10 l-|||-(1)-|||-(2)