题目
8电池(s)|Zn(Cl)_(2)(0.555molcdot (Kg)^-1)|AgCl(s)|Ag(s)，测得25℃时电动势(s)|Zn(Cl)_(2)(0.555molcdot (Kg)^-1)|AgCl(s)|Ag(s)。已知：(s)|Zn(Cl)_(2)(0.555molcdot (Kg)^-1)|AgCl(s)|Ag(s)，(s)|Zn(Cl)_(2)(0.555molcdot (Kg)^-1)|AgCl(s)|Ag(s)。（1）写出电池反应（得失电子数为2）；（2）求上述反应的标准平衡常数(s)|Zn(Cl)_(2)(0.555molcdot (Kg)^-1)|AgCl(s)|Ag(s)；（3）求溶液(s)|Zn(Cl)_(2)(0.555molcdot (Kg)^-1)|AgCl(s)|Ag(s)的平均离子活度因子(s)|Zn(Cl)_(2)(0.555molcdot (Kg)^-1)|AgCl(s)|Ag(s)。For cell(s)|Zn(Cl)_(2)(0.555molcdot (Kg)^-1)|AgCl(s)|Ag(s), at 25℃(s)|Zn(Cl)_(2)(0.555molcdot (Kg)^-1)|AgCl(s)|Ag(s).Given(s)|Zn(Cl)_(2)(0.555molcdot (Kg)^-1)|AgCl(s)|Ag(s)，(s)|Zn(Cl)_(2)(0.555molcdot (Kg)^-1)|AgCl(s)|Ag(s).(1)Write out cell reaction ((s)|Zn(Cl)_(2)(0.555molcdot (Kg)^-1)|AgCl(s)|Ag(s))(2)Calculate (s)|Zn(Cl)_(2)(0.555molcdot (Kg)^-1)|AgCl(s)|Ag(s)of the above cell reaction .(3)Calculate (s)|Zn(Cl)_(2)(0.555molcdot (Kg)^-1)|AgCl(s)|Ag(s)of the (s)|Zn(Cl)_(2)(0.555molcdot (Kg)^-1)|AgCl(s)|Ag(s) solution.
8电池
，测得25℃时电动势
。已知：
，
。
（1）写出电池反应（得失电子数为2）；
（2）求上述反应的标准平衡常数
；
（3）求溶液
的平均离子活度因子
。
For cell, at 25℃.Given
，.
(1)Write out cell reaction (
)
(2)Calculate of the above cell reaction .
(3)Calculate of the solution.
题目解答
答案
(1)Zn+2AgCl(s) === ZnCl2（b=0.555mol·kg1）+2Ag;(2) 
(3) 