题目

事件A_(1),A_(2),...,A_(n)相互独立，则P(A_(1)cup A_(2)cup ... cup A_(n))=（）。A. P(overline(A_{1)})+P(overline(A_{2)})+...+P(overline(A_{n)})B. 1-P(overline(A_{1)})P(overline(A_{2)})... P(overline(A_{n)})C. P(A_(1))+P(A_(2))+...+P(A_(n))D. 1-P(A_(1))P(A_(2))... P(A_(n))

事件$A_{1},A_{2},\cdots,A_{n}$相互独立，则$P(A_{1}\cup A_{2}\cup \cdots \cup A_{n})=$（）。

A. $P(\overline{A_{1}})+P(\overline{A_{2}})+\cdots+P(\overline{A_{n}})$

B. $1-P(\overline{A_{1}})P(\overline{A_{2}})\cdots P(\overline{A_{n}})$

C. $P(A_{1})+P(A_{2})+\cdots+P(A_{n})$

D. $1-P(A_{1})P(A_{2})\cdots P(A_{n})$

题目解答

B. $1-P(\overline{A_{1}})P(\overline{A_{2}})\cdots P(\overline{A_{n}})$