2.填空题现有32位IEEE754标准的浮点数X=3D350000H，求其对应的二进制[1]真值数。解：3D350000H=（______）BSf=（______），E=（______）B，M=（______）Be=（______）B（二进制真值数）m=（______）B（二进制真值数）X=（______）B（二进制真值数）

将 $ 3D350000_H $ 转换为二进制得： \[ 3D350000_H = 00111101001101010000000000000000_B \] 分解得： \[ S_f = 0, \quad E = 01111010_B, \quad M = 01101010000000000000000_B \] 实际指数 $ e = 122 - 127 = -5 $，尾数 $ m = 1.0110101_B $。 最终结果为： \[ X = 1.0110101_B \times 2^{-5} = 0.000010110101_B \] 答案： \[ 3D350000_H = 00111101001101010000000000000000_B \] \[ S_f = 0, \quad E = 01111010_B, \quad M = 01101010000000000000000_B \] \[ e = -5_B, \quad m = 1.0110101_B \] \[ X = 0.000010110101_B \]