题目
一般的矩形截面钢筋混凝土剪扭构件,考虑剪扭相关作用,其受扭承载力计算公式是()。A. T_u = 0.35beta_1f_tW_t + 1.2sqrt(xi)f_(xy)(A_(st1)A_(cor))/(s)B. T_u = 0.35alpha_3f_tW_t + 1.2sqrt(xi)f_(xy)(A_(st)A_(cor))/(s)C. T_u = 0.35f_tW_t + 1.2sqrt(xi)(f_(xy)A_(st)A_(cor))/(s) + 0.07(N)/(A)W_tD. T_u = beta_1(0.35f_tW_t + 0.07(N)/(A)W_t)+ 1.2sqrt(xi)f_(xy)(A_(st)A_(cor))/(s)
一般的矩形截面钢筋混凝土剪扭构件,考虑剪扭相关作用,其受扭承载力计算公式是()。
A. $T_u = 0.35\beta_1f_tW_t + 1.2\sqrt{\xi}f_{xy}\frac{A_{st1}A_{cor}}{s}$
B. $T_u = 0.35\alpha_3f_tW_t + 1.2\sqrt{\xi}f_{xy}\frac{A_{st}A_{cor}}{s}$
C. $T_u = 0.35f_tW_t + 1.2\sqrt{\xi}\frac{f_{xy}A_{st}A_{cor}}{s} + 0.07\frac{N}{A}W_t$
D. $T_u = \beta_1\left(0.35f_tW_t + 0.07\frac{N}{A}W_t\right)+ 1.2\sqrt{\xi}f_{xy}\frac{A_{st}A_{cor}}{s}$
题目解答
答案
D. $T_u = \beta_1\left(0.35f_tW_t + 0.07\frac{N}{A}W_t\right)+ 1.2\sqrt{\xi}f_{xy}\frac{A_{st}A_{cor}}{s}$