题目
箱形截面钢筋混凝土一般剪扭构件,考虑剪扭相关作用,其受扭承载力计算公式是()。A. T_u = 0.35beta_i f_t W_t + 1.2sqrt(xi) f_(xy) (A_(st) A_(cor))/(s)B. T_u = 0.35alpha_i f_t W_t + 1.2sqrt(xi) f_(xy) (A_(st) A_(cor))/(s)C. T_u = 0.35f_t W_t + 1.2sqrt(xi) (f_(xy) A_(st) A_(cm))/(s) + 0.07 (N)/(A) W_tD. T_u = beta_i (0.35f_t W_t + 0.07 (N)/(A) W_t )+ 1.2sqrt(xi) f_(xy) (A_(st) A_(cor))/(s)
箱形截面钢筋混凝土一般剪扭构件,考虑剪扭相关作用,其受扭承载力计算公式是()。
A. $T_u = 0.35\beta_i f_t W_t + 1.2\sqrt{\xi} f_{xy} \frac{A_{st} A_{cor}}{s}$
B. $T_u = 0.35\alpha_i f_t W_t + 1.2\sqrt{\xi} f_{xy} \frac{A_{st} A_{cor}}{s}$
C. $T_u = 0.35f_t W_t + 1.2\sqrt{\xi} \frac{f_{xy} A_{st} A_{cm}}{s} + 0.07 \frac{N}{A} W_t$
D. $T_u = \beta_i \left(0.35f_t W_t + 0.07 \frac{N}{A} W_t \right)+ 1.2\sqrt{\xi} f_{xy} \frac{A_{st} A_{cor}}{s}$
题目解答
答案
D. $T_u = \beta_i \left(0.35f_t W_t + 0.07 \frac{N}{A} W_t \right)+ 1.2\sqrt{\xi} f_{xy} \frac{A_{st} A_{cor}}{s}$